Question

find cubic polynomial with sum , sum of the product of the zero taken 2 at the same time with zero as 3 , -1 , -3

Answer 1

Answer:

k(x³+x²+3x-7)

Step-by-step explanation:

∝=3 , β=-1 , ω(you think this as gamma)=-3

αβω = -d/a

α+β+ω = -b/a

αβ+βω+ωα = c/a

k(x³-(α+β+ω)x²+(αβ+βω+ωα)x-αβω) this is cubic formula

k(x³-(3-1-3)x²+(3*-1-1*-3-3*1)x-3-1-3)

k(x³+1 x²+3x-7)

k(x³+x²+3x-7)

αβω=7/1=7

αβ+βω+ωα=3

α+β+ω=-1/1=1

mark me as brainliest