find current???...do it with explanation
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When the circuit is balanced , current across the galvanometer ( not given here ) will be zero .
From top ,
2 Ω , 2 Ω are connected in series ,
➠
➠
From below too ,
2 Ω , 2 Ω are connected in series ,
➤
➤
Now , are connected in parallel ,
➙
➙
➙
➙
➙
Apply Ohm's law ,
⭆
⭆ 4 = I (2)
⭆ I = 4 / 2
⭆ I = 2 A
So , Current drawn from the battery is 2 A .
AbhinavRocks10:
hmmm............... really
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