Question

Find current through 10 ohm resistor using Thevenin's Theorem​

Answer 1

Answer:

Hence, the equivalent Thevenin's source with respect to terminals A and B is as shown in Fig. When 10 Ω resistance is reconnected across A and B, current through it is I = 6.24/(9.43 + 10) = 0.32 A.

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Answer 2

Given:

A network of resistors and batteries (attached below)

To find:

Current via 10 ohm resistor

Solution:

Applying KCL at node C:

 I₁ + I₃ - I₂ = 0

or   $\frac{V_1 - V_o_c}{r_1} +\frac{V_3 - V_o_c}{r_3} - \frac{V_o_c + V_2}{r_2} = 0$

substituting values and solving, we get:

-o.5Voc  - Voc - O.2 Voc = 2.4 - 20 -5

or Voc = 13.29V

Removing the independent voltage sources via short circuits, we get:

1/Rth = 1/2 + 1/5 + 1/1

= 10/17 = 0.58

Current via r₄ = I₄ = Voc / Rth + r₄

= 13.29 / 0.58+10

= 1.26A

Hence, the current via 10 ohm resistor is 1.26A.