find current through 4 ohm 2 ohm and 3 ohm connected to a battery of 4 v three of them in parallel combination
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Given :
• R1 = 4 Ohms
• R2 = 2 Ohms
• R3 = 3 Ohms
• Potential Difference = 4 V
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To Find :
• Current in circuit when all are connected in parallel.
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Solution :
⇒1/R_{eq} = 1/R1 + 1/R2 + 1/R3
⇒1/R_{eq} = 1/4 + 1/2 + 1/3
⇒1/R_{eq} = (3 + 6 + 4)/12
⇒1/R_{eq} = 13/12
⇒ R_{eq} = 12/13
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⇒V = IR
⇒4 = I * 12/13
⇒I = 4 * 13/12
⇒ I = 13/3
⇒I = 4.33 A
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