Question

Find curved surface area of cylinder whose radius and height are 4.2 and 14 cm ​

Answer 1

${\large{\pmb{\sf{\underline{RequirEd \; Solution...}}}}}$

Given that:

• Radius of the cylinder is 4.2 cm

• Height of the cylinder is 14 cm

To find:

• Curved Surface Area or the Lateral Surface Area of the cylinder

Solution:

• Curved Surface Area or the Lateral Surface Area of the cylinder = 369.264 cm sq.

Some formulas:

$\; \; \; \; \; \; \;{\sf{\leadsto Volume \: of \: cylinder \: = \: \pi r^{2}h}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Surface \: area \: of \: cylinder \: = \: 2 \pi rh + 2 \pi r^{2}}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Lateral \: area \: of \: cylinder \: = \: 2 \pi rh}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Base \: area \: of \: cylinder \: = \: \pi r^{2}}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Height \: of \: cylinder \: = \: \dfrac{v}{\pi r^{2}}}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Radius \: of \: cylinder \: = \:\sqrt \dfrac{v}{\pi h}}}$

Using concept: Formula to find out the Curved Surface Area or the Lateral Surface Area of the cylinder.

Using formula: The Curved Surface Area or the Lateral Surface Area of the cylinder is given by 2πrh

• (Where, π is pronounced as pi, the value of π is 22/7 or 3.14, r denotes radius and h denotes height)

Full Solution:

~ We just have to use the given formula and have to put the values according to this and at last we will get our final result!

››› CSA = 2πrh

››› CSA = 2(3.14)(4.2)(14)

››› CSA = 6.28(4.2)(14)

››› CSA = 26.376(14)

››› CSA = 369.264 cm sq.

Henceforth, 369.264 cm sq. is the curved surface area of the cylinder or the lateral surface area.

Cylinder structure:

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{r}}\put(9,17.5){\sf{h}}\end{picture}$