find d^2y/dx^2 , if x=a cos t , y= b sin t
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Answer:
Ans :- - b/a(cosec^3t)
Step-by-step explanation:
x=a cos t
dx/dt= a(-sin t) = -a sint
y= b sin t
dy/dt=b cost
dy/dx=b cost/-a sint=-b/a cot t
d^2y/dx^2= - b/a(-cosec^2t)dt/dx
= b/a(cosec^2 t) (-1/sint)
=b/a(-cosec^3t)
=-b/a(cosec^3 t)
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