Question

find d compound interest if amount = rs.4000 and principal = rs.2445​

Answer 1

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$\LARGE\textsf{\underline\textcolor{aqua}{↭ GiVeN :-}}$

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$\qquad\tt{:}\longrightarrow\large\textsf{Amount = Rs. 4000}$

$\qquad\tt{:}\longrightarrow\large\textsf{Principal = Rs. 2445}$

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$\LARGE\textsf{\underline\textcolor{aqua}{↭ To FiNd :-}}$

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• Compound Interest = ?

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$\LARGE\textsf{\underline\textcolor{aqua}{↭ FoRmUlA :-}}$

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$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{purple}{Amount = Principal + Compound Interest}}$

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$\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTioN :-}}$

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$\qquad\tt{:}\longrightarrow\large\textsf{Amount = Principal + Compound Interest}$

$\qquad\tt{:}\longrightarrow\large\textsf{4000 = 2445 + Compound Interest}$

$\qquad\tt{:}\longrightarrow\large\textsf{4000 - 2445 = Compound Interest}$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{1555 = Compound Interest}}$

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$\large\textsf\textcolor{orange}{∴ Compound Interest = Rs. 1555}$

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$\LARGE\textsf{\underline\textcolor{aqua}{↭ MoRe fOrMuLaS :-}}$

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$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{purple}{ C.I. =P \left(1 + \cfrac{\large\textsf{R}}{\large\textsf{100}}\right)^{\large\textsf{n}} }}$

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$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{purple}{S.I. = \cfrac{\large\textsf{P × T × R}}{\large\textsf{100}} }}$

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• T = TIME PERIOD
• P = PRINCIPAL
• R = RATE OF INTREST
• S.I. = SIMPLE INTREST
• C.I. = COMPOUND INTEREST

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Answer 2

Answer:

P=Rs. 4000

R=6%

T=3 years

A=P(1+100R)T

=4000(1+1006)3

=4000(100106)3

=4000×100×100×100106×106×106

=125595508=4764.064

Compound Interest=A−P

=4764.064−4000

= Rs. 764.064.