Question

find d/dt (3t^2+2t+1)

Answer 1

Answer:

it's 6t + 2

Explanation:

hope it helps :)

Answer 2

Explanation:

$\sf \frac{d(3{t}^{2} + 2t + 1 )}{dt} \\ \\ \sf = \frac{d(3{t}^{2})}{dt} + \frac{d(2t)}{dt} + \frac{d(1)}{dt} \\ \\ \sf = 6t + 2$

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