Question

find d/dx [ 15 log (x) ]​

Answer 1

$\implies \dfrac{d(15 log(x) \: ) }{dx}$

$\implies15 \times \dfrac{d(log(x) \: ) }{dx}$

We know that :-

• d(log t)/dt = 1/t

using Chain rule:-

$\implies15 \times \dfrac{1}{x} \times \dfrac{d(x) }{dx}$

$\implies15 \times \dfrac{1}{x} \times 1$

$\implies \dfrac{15}{x}$

Answer :

$\dfrac{d(15 log(x) \: ) }{dx} = \dfrac{15}{x}$

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Learn more :-

d(x^n)/dx = n x^(n-1)

d(log x)/dx = 1/x

d(e^x)/dx = e^x

d(sinx)/dx = cosx

d(cos x)/dx = -sin x

d(cosec x)/dx = -cot x cosec x

d(tan x)/dx = sec²x

d(sec x)/dx = secx tanx

d(cot x)/dx = - cosec² x

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