find d÷dx(2x^2+5x+2)
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Answer:
heya mate there's your answer
d/dx(2x^2+5x+2)=2(2)x^1+5(1)+0
=4x+5
[as d/dx(x^n)=nx^n-1
and d/dx(constant)=0]
hope it helps you
Thank you
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