Question

find : d/dx log(5×+7) ​

Answer 1

Step-by-step explanation:

y=log5(x)y=log5(x)

The derivative of log5(x)log5(x) with respect to xx is 1xln(5)1xln(5).

1xln(5)1xln(5)

y=log5(x)y=log5⁡(x)

+2+2

−1-1

−2-2

Answer 2

Step-by-step explanation:

( log 7 x ) , find d yd x ...

Given y = log5(log7x) dydx = ddxlog5 (logxlog7) = log5 (1xlog710) dydx