find : d/dx log(5×+7)
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Answered by
2
Step-by-step explanation:
y=log5(x)y=log5(x)
The derivative of log5(x)log5(x) with respect to xx is 1xln(5)1xln(5).
1xln(5)1xln(5)
y=log5(x)y=log5(x)
+2+2
−1-1
−2-2
Answered by
4
Step-by-step explanation:
( log 7 x ) , find d yd x ...
Given y = log5(log7x) dydx = ddxlog5 (logxlog7) = log5 (1xlog710) dydx
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