Math, asked by Richyron, 1 year ago

Find d/dx of log(sin(logx))

Answers

Answered by kaurInderpreet11
1
plzz check it
I Am right ya wrong plzz tell me
Attachments:

Richyron: answer is cosx(logx)/x. sin(logx)
kaurInderpreet11: I Am wrong plzz tell me
rakeshmohata: yup
nav17: hlo
nav17: hii
Answered by rakeshmohata
1
Here is ur required answer brother..
Attachments:

rakeshmohata: yup
rakeshmohata: I can teach u if u dont mind
kaurInderpreet11: answer is Cosx( Logx) /x . sin (logx)
rakeshmohata: yup
rakeshmohata: cosx/sinx = cotx
rakeshmohata: so coslogx/sinlogx=cotlogx
kaurInderpreet11: no cos vala and sin wala to multiply me hai divide Mai nhi
rakeshmohata: log का karte h.. तो वो denominator मे आता h
rakeshmohata: so sin denominator मे h..
Richyron: ha
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