Question

Find
d/dx ( x4-2sinx + 3cosx )​

Answer 1

Answer:

=d/dx(x^4)-2d/dx(sinx)+3d/dx(cosx)

=4(x^4-1)-2cosx+3(-sinx) d/dx(sinx)=cosx

d/dx(cosx)=-sinx

Answer=4x^3-2cosx-3sinx

d/dx(x^a)=a(x^a-1)