Question

find d for an AP if tn=7, tn+1=10​

Answer 1

Answer:

d = 3

Step-by-step explanation:

tn= a+(n-1)d ....(1)

t(n+1)= a+nd....(2)

(2)-(1),

d=3

Answer 2

Given Data :

• $\sf { { }^{ \large t} {n}^{ \:} } = 7$
• $\sf ( { \: }^{ \large d} {n}^{ \: } + 1)= 10$

To find :

• Common Difference (d) = ?

Solution :-

$\sf { \:}^{ \large t} {n}^{ \: } = a + (n - 1)d$

then ,