Question

find d For an AP, S20 = 610, a=2 ​

Answer 1

Answer:

Given (a) first term of AP = 2

n total terms = 20

(a  

n

​

) least term = 59

We know a  

n

​

=a+(n−1)d

59−2=19d

d=  

19

57

​

=3

∴ common difference of AP is .

For finding 6  

th

 term from last.

out first term = 52 and last term = 2 & common difference = -3

now

a  

6

​

=a+5d=59+5(−3)

a  

6

​

=59−15

[a  

6

​

=44]

∴6  

th

 term from last is 44.

Step-by-step explanation:

here you go