Question

find d of ap whose first term is 4 last term is 49 and sum of its terms is 265

Answer 1

an = a + (n-1) d
49-4=(n-1) d
45/d-1=n .....1
sn =n/2 (a + an)
265 ×2= n × 53
265 ×2 /53 =n
n = 10
in eq 1
45 = 9d
d = 5

Answer 2

Hey !!! ^_^

Here is your answer

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In attachment

Given ...

fisrt term (a) = 4 ...

Last term (l) = 49

and Sn = 265 ....

Using the the formula of Ap ...

Sn = n/2{ a + l) ..

U got the value of ..D ..

That is Common difference is 5..

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I HOPE IT WILL HELP YOU

Thank you

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