Question

Find d smallest no when divided by 5,6,7,8 and gives d remainder 3 in each case but it is exactly divided by 9?

Answer 1

Answer: 1683

Step-by-step explanation:

let m be smallest number when divided by 5,6,7 and 8 gives d remainder 3.

then m-3 will be the lcm of 5,6,7 and 8

So m-3=840

So m = 843

But this number is not divisible by 9. So we need to look through the multiples of 840

840x2=1680

1680+3=1683, is a multiple of 9