Find d (T, A) when, T → 1 and A → 4.
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Answered by
1
Answer:
Explanation:
To find acceleration at time t, we have to differentiate the position vector twice.
Differentiating the first time gives the velocity:
v(t) = r'(t) = 12t3i + 12tj
Differentiating a second time gives the accelaration:
a(t) = r''(t) = 36t2i + 12j
Plug in t=1 to solve for the final answer:
a(1) = r''(1) = 36i + 12j
❌*AtTiTuDe*❌
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2
Step-by-step explanation:
the above answer is correct
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