Find d value of k, following point re collinear (7,-2),(5,1),(3,k)
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Heyy mate ❤✌✌❤
Here's your Answer...
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Since, The points are collinear.
Therefore, Area of Triangle = 0
1/2 [x1(y2-y3)+x2 (y3-y1) + x3(y1-y2)] = 0
[7(1-k) + 5(k+2) + 3(-2-1)]=0
7-7k +5k+10-9 = 0
8-2k=0
2k=8
k=8/2 = 4.
✔✔
Here's your Answer...
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Since, The points are collinear.
Therefore, Area of Triangle = 0
1/2 [x1(y2-y3)+x2 (y3-y1) + x3(y1-y2)] = 0
[7(1-k) + 5(k+2) + 3(-2-1)]=0
7-7k +5k+10-9 = 0
8-2k=0
2k=8
k=8/2 = 4.
✔✔
Anonymous:
ye kya hova, status ghaieb
Answered by
0
1/2 [x1(y2-y3)+x2 (y3-y1) + x3(y1-y2)] = 0
[7(1-k) + 5(k+2) + 3(-2-1)]=0
7-7k +5k+10-9 = 0
8-2k=0
2k=8
k=8/2 = 4
Hope that this answer will help you ❤️✨❤️
[7(1-k) + 5(k+2) + 3(-2-1)]=0
7-7k +5k+10-9 = 0
8-2k=0
2k=8
k=8/2 = 4
Hope that this answer will help you ❤️✨❤️
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