Math, asked by shine142, 11 months ago

find d value of k if (y-3) is a factor of 4y^3+3y^2-4y+k​

Answers

Answered by streetburner
2

Answer:

-123

Step-by-step explanation:

Let p(x) = 4y^3+3y^2-4y+k

y-3 is factor of p(x) = 4y^3+3y^2-4y+k

Means, p(3) = 0

4*27+3*9-4*3+k = 0 or, 108 + 27 - 12 + k = 0

108+15+k = 0

k = -123

Answered by niral
0

Answer:

Step-by-step explanation:

→ If (y-3) is a factor of p(y) = 4y³ + 3y² - 4y + k

→ (y-3)=0

→ y = 3

→ p(y) = 4y³ + 3y² - 4y + k

→ p(3) = 4(3)³ + 3(3)² - 4(3) + k

       = 4(27) + 3(9) - 12 + k

       = 108 + 27 - 12 + k

       = 123 + k

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