Find (D² - 6D+9) y =e^3x
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Complimentary function
Auxiliary equation (m-3)(m-3) =0 m=3,3 repeated root.
yc=(C1x+C2)e3x
Particular Integral
yp=1(D−3)2x3e3x
By operator shift theorem
1f(D)(eaxg(x))=eax1f(D+a)g(x)
accordingly yp=e3x1D2x3
Since D means differentiation and 1D means integration
yp=∫∫x3dxdx=x520
y=yc+yp=(C1x+C2)e3x+x520
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