Question

find d²y/dx² if y=x³logx​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$y = {x}^{3} \times log(x)$

APPLYING THE PRODUCT RULE

$\frac{dy}{dx} = 3 {x}^{2} log(x) + {x}^{2} \\ \frac{ {d}^{2}y }{d {x}^{2} } = 6x log(x) + 3x + 2x \\ = > x(6 log(x) + 5)$

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