Question

Find DC from the given figure and find perimeter of triangle ABC




Abhi answer kardo....​

Answer 1

Answer:

$\huge\mathfrak\blue{\fcolorbox{green}{ANSWER:-}}$

Here given that

AB=25

AD=14cm

BD bisects AC

BC=40

here m<ADB=90°

=>triangle ADB is a right triangle

so

AD=perpendicular(height)

BD=Base

AB=hypertenous

in a right triangle ,

according to Pythagorean theory

$\large\blue{\boxed{{p}^{2}+{b}^{2}={h}^{2}}}$

=>b=$\squrt{h}^{2}-{p}^{2}$

=$\squrt{23}^{2}-{14}^{2}$

=$\squrt{529}-{196}=\squrt{324}[/tex</p><p>=18</p><p>hence DB=18</p><p>in triangle DBC,m <BDC=90°</p><p>CD=perpendicular(height)</p><p>BD=base</p><p>BC=hypertenous</p><p>=> according to Pythagorean theory</p><p>CD=[tex]\squrt{40}^{2}-{18}^{2}=\squrt{1600}-{324}=\squrt{1296}=34$

=>AC=CD+AD

=18+34

=52

the perimeter of triangle ABC=AB+BC+AC

=52+40+23

=115

Hence DP=18cm and The perimeter of triangle ABC=115

Answer 2

Answer:

25 + 40 + 14

79 is the perimeter

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