Question

find de Broglie wavelength of a Neutron in thermal equilibrium with heavy water. given temperature of heavy water=27°C and mass of neutron = 1.66×10^-27 kg. give me correct answer no spam​

Answer 1

Here, T = 273 + 27 = 300K

m = 1.66 × 10^-27 kg

using, lemda = h / √3mkT

=6.62× 10^-34/√3×1.66×10^-27×1.38×10^-23×300

=1.46×10^-9m

= 1.46nm

hope it will help uh...yo

Answer 2

Answer:

Explanation:

thermal neutrons are used in nuclear power plant for initiate chain reaction.

So they are accelerated thermally,so called thermal neutrons.

their kinetic energy is given by Maxwell's theory in thermodynamics that is (3÷2)kT.

here k is Boltzmann constant.

de Broglie wavelength is given by h÷[√(2.m.K)] here K is kinetic energy of matter.

so replace K by (3÷2)kT.

It will give u wavelength= h÷[√(3mkT)]

where h is planks constant

k is Boltzmann constant

T is temperature in Kelvin.