Question

find degree measure ofan angle which is 4/5 of its supplement ​

Answer 1

Let the supplement angle be X

Then, angle be (4/5) of X = 4x/5

ATQ,

x + 4x/5 = 180°

(5x + 4x)/5 = 180°

9x = 180×5

x= (180×5)/9

x = 100°

then,

x= 100°

4x/5 = (4×100)/5 = 400/5 = 80°

Thus,

angles are 80° & 100°

hope it help u

Answer 2

Answer:

thanks..................