find degree of hardness of water sample in terms of ppm of caco3 if sample contains 10^-3 M CaCl2 and 0.05M NaCl
Answers
Answer:
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The degree of hardness of water sample is 100 ppm
Explanation:
The hardness of water is the concentration of multivalent cations
Therefore, in the given sample of water, the hardness will be only due to CaCl₂
Molarity of CaCl₂ = 0.001 M
i.e. in 1 litre, the moles of CaCl₂ = 0.001
Molecular weight of CaCl₂ = 111
Thus, the weight of CaCl₂ = 0.001 × 111 = 0.111 gram
Now,
Gram equivalents of CaCl₂ = Gram equivalents of CaCO₃
Weight of CaCl₂/Equivalent Weight of CaCl₂ = Weight of CaCO₃/Equivalent weight of CaCO₃
or, 0.111/(111/2) = Weight of CaCO₃/(100/2)
or, 2 x 10⁻³ = Weight of CaCO₃/50
or, Weight of CaCO₃ = 50 x 2 x 10⁻³
= 0.1 gram
= 100 mg
Thus, the hardness as of CaCO₃ = 100 mg/lt = 100 ppm
Therefore, the degree of hardness of water sample = 100
Hope this answer is helpful.
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