find derivation of 2x+3 from 1st principle..
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Let, f(x) = 2x + 3
Now,
lim h→0 f(x+h)-f(x) / h
= lim h→0 2(x+h)-2x / h
= lim h→0 {2(x+h)-2x}{2(x+h)+2x} / h{2(x+h) + 2x}
= lim h→0 4(x+h)²-4x² / h{2(x+h) + 2x}
(Simplify it)
= lim h→0 (4h² + 8xh) / h{2(x+h) + 2x}
= lim h→0 h(4h+8x) / h{2(x+h) + 2x}
= 4(0) + 8x / 2(x+0) + 2x
(Put value h=0)
= 8x / 4x = 2
This is your answer
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