find derivative of=(3cosx-4sinx)/5
Answers
Answered by
1
Answer: -1/5(3sinx+4cosx)
Step-by-step explanation:
y = (3cosx - 4 sinx)/5
dy/dx = 1/5(3cosx - 4sinx)d/dx
dy/dx = 1/5(3(-sinx) - 4(cosx))
dy/dx = -1/5(3sinx + 4cosx)
Answered by
1
Answer:
Step-by-step explanation:
d/dx(3cosx-4sinx)/5
(5 d/dx (3cosx-4sinx)-d/dx5 (3c0sx-4sinx))^25
5(-3sinx-4cosx)-0^25
-3sinx-4cosx^5
-1/5(3sinx+4cosx)
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