Question

find derivative of=(3cosx-4sinx)/5​

Answer 1

Answer: -1/5(3sinx+4cosx)

Step-by-step explanation:

y = (3cosx - 4 sinx)/5

dy/dx = 1/5(3cosx - 4sinx)d/dx

dy/dx = 1/5(3(-sinx) - 4(cosx))

dy/dx = -1/5(3sinx + 4cosx)

Answer 2

Answer:

Step-by-step explanation:

d/dx(3cosx-4sinx)/5

(5 d/dx (3cosx-4sinx)-d/dx5 (3c0sx-4sinx))^25

5(-3sinx-4cosx)-0^25

-3sinx-4cosx^5

-1/5(3sinx+4cosx)