Question

Find derivative of 3x^2+4x+2÷underoot x

Answer 1

Solution :

$\sf {\bold { \bigstar Here \: we \: have \: to \: find \: the \: derivative \: of \: \implies }} \\ \\ \sf{ \bold {\rightarrow \dfrac{ 3x^2 + 4x + 2}{\sqrt{x}}}} \\ \\ \sf{ \bold {\rightarrow \dfrac{d}{dx} [ 3x^{2+\frac{-1}{2}} + 4x^{1+\frac{-1}{2}} + 2x^{\frac{-1}{2}} ] }} \\ \\ \sf{ \bold{ \rightarrow \dfrac{d}{dx} [3x^{\frac{3}{2}} + 4x^{\frac{1}{2}} + 2x^{\frac{-1}{2} }] }} \\ \\ \sf{ \bold {\rightarrow \dfrac{d}{dx}[3x^{\frac{3}{2}}] + \dfrac{d}{dx}[ 4x^{\frac{1}{2}} ] + \dfrac{d}{dx}[ 2x^{\frac{-1}{2} }] }} \\ \\ \sf{ \bold {\rightarrow 3 \dfrac{d}{dx}[x^{\frac{3}{2}}] + 4\dfrac{d}{dx}[ x^{\frac{1}{2}} ] + 2\dfrac{d}{dx}[ x^{\frac{-1}{2} }] }}$

This will be 3 . 3/2 . x^1/2 + 4 . 1/2 , x^(-1/2) + 2.-1/2 . x^(-1/2-1)

>> 9/2 x½ + 2 x^-½ - x^(-3/2)

Answer 2

$\bf \red{Gɪᴠᴇɴ :}$

$\: \: \: \: \: \: \: \bullet \: ➛ \rm \: \frac{ {3x}^{2} + 4x + 2 }{ \sqrt{x} }$

$\bf \red{Tᴏ Fɪɴᴅ :}$

$\: \: \: \: \: \: \: \: \: \: \: \bullet \: ➛ \rm \: \frac{ {3x}^{2} + 4x + 2 }{ \sqrt{x} }$

$\bf \red{Sᴏʟᴜᴛɪᴏɴ :}$

➠ See the above attachment .

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@Shivam

#Bebrainly