find derivative of above
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f'(x)=3cos3x+3sin3x.
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➡HERE IS YOUR ANSWER⬇
f(x) = sin3x - cos3x .....(i)
Now, differentiating both sides of (i) with respect to x, we get '
f'(x) = 3cos3x + 3sin3x
= 3 (cos3x + sin3x)
Rules :
⬆HOPE THIS HELPS YOU⬅
f(x) = sin3x - cos3x .....(i)
Now, differentiating both sides of (i) with respect to x, we get '
f'(x) = 3cos3x + 3sin3x
= 3 (cos3x + sin3x)
Rules :
⬆HOPE THIS HELPS YOU⬅
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