Question

find derivative of f(x)=x²tanx​

Answer 1

Answer:

$\frac{x}{ \cos(x) } (x \sec(x) + 2 \sin(x) )$

Step-by-step explanation:

$f(x) = {x}^{2} \tan(x)$

$f'(x) = \frac{d}{dx} ({x}^{2} \tan(x) )$

$f'(x) = {x}^{2} d( \tan(x) ) + d( {x}^{2}) \tan(x) \\ \\ = {x}^{2} \sec ^{2} (x) + 2x \tan(x)$

$= \frac{x}{ \cos(x) } (x \sec(x) + 2 \sin(x) )$

Hope it helps