Question

Find derivative of ln 1/√(6x)

Answer 1

Step-by-step explanation:

$\frac{d \: \: ln( \frac{1}{ \sqrt{6x} } ) }{dx} \\ = \sqrt{6x} \times \frac{d \frac{1}{ \sqrt{6x} } }{dx} \\ = \sqrt{6x} \times - \frac{1}{2} {(6x)}^{ - \frac{3}{2} } \\ = - \sqrt{6x} \times \frac{1}{2} \times \frac{1}{ {( \sqrt{6x)} }^{3} } \\ = - \frac{1}{2} \times \frac{1}{6x} \\ = - \frac{1}{12x}$