Question

Find derivative of log (sin (1+2x)^1/2

Answer 1

Answer:

$= > \frac{d(log({ \sin(1 + 2x) }^{ \frac{1}{2} } ) }{dx} = \frac{1}{ \sin( \sqrt{1 + 2x} ) } \times \cos( \sqrt{1 + 2x} ) \\ = \tan( \sqrt{1 + 2x} )$

Hope this answer helps you ^_^ !