Math, asked by manavgaygole, 3 months ago

find derivative of (sec3x + tan3x)

Answers

Answered by anzthakur876p7hp84

0

Step-by-step explanation:

d/dx(sec3x+tan3x)

=sec3xtan3x*d/dx(3x)+ sec^2(3x)* d/dx(3x)

= sec3xtan3x*(3)+ sec^2(3x)(3)

=3sec3x(tan3x+sec3x)

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