find derivative of (x/a)^n+(y/b)^n= C
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Correct option is D
Given
(ax)n+(by)n=2
Differentiating both sides w.r.t x, we get
an(ax)n−1+bb(by)n−1×dxdy=0
⇒=−an(ax)n−1×ab(yb)n−1
∴dxdy at (a,b)=ab
∴ Tangent is y−b=−ab(x−a)⇒bx+ay=2ab⇒ax+by=2
for all values of n (∵dxdy is independent of n)
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