Math, asked by srijalulak24054, 3 months ago

Find derivative of x^Sinhx

Answers

Answered by Anonymous

Step-by-step explanation:

(sinhx)′=(ex−e−x2)′=ex+e−x2=coshx,(coshx)′=(ex+e−x2)′=ex−e−x2=sinhx. We can easily obtain the derivative formula for the hyperbolic tangent: (tanhx)′=(sinhxcoshx)′=(sinhx)′coshx−sinhx(coshx)′cosh2x=coshx⋅coshx−sinhx⋅sinhxcosh2x=cosh2x−sinh2xcosh2x.

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