find derivative of x^x by first principle.
Answers
Answered by
0
please refer to the following attachment below and hope it helps you
actually I am not sure about the answer as present I am in class 9th and I am not perfect in it
But anyways
All the best for your future..
Attachments:
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Answered by
0
−1h=y⟺x=limn→∞(1+yn)n⟺x=ey⟺y=log(x)
lim
h
→
0
x
h
−
1
h
=
y
⟺
x
=
lim
n
→
∞
(
1
+
y
n
)
n
⟺
x
=
e
y
⟺
y
=
log
(
x
)
Then,
limh→0(x+h)x+h−xxh
lim
h
→
0
x
h
−
1
h
=
y
⟺
x
=
lim
n
→
∞
(
1
+
y
n
)
n
⟺
x
=
e
y
⟺
y
=
log
(
x
)
Then,
limh→0(x+h)x+h−xxh
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