Question

find derivative of y=(4x^2 - 2x + 1)^-2 , dy/dx​

Answer 1

y=(4x²-2x+1)^-2

dy/dx=-2(4x²-2x+1)^-3 .(8x-2)

Answer 2

Answer:-4(4x-1)/(4(x^2)-2x+1)^3

Step-by-step explanation:

Let take u=4(x^2)-2x+1 and du/dx= 2(4x-1)

Y= u^-2

dy/dx= -2(u^-3)du/dx.

dy/dx= -2((4(x^2)-2x+1)^-3)2(4x-1)

= -4(4x-1)(4(x^2)-2x+1)^-3