Question

Find derivative of y=
log (sec3x & tan3x)​

Answer 1

Step-by-step explanation:

y= log(sec3xtan3x)

= log(sec3x) +log(tan3x)

dy/dx= [1/sec3x*d/dx(sec3x)]+[1/tan3x*d/dx(tan3x)]

= (1/sec3x)* sec(3x)tan(3x) *d/dx(3x)+ (1/tan3x) *sec^2(3x)*d/dx(3x)

= tan3x*(3)+(1/tan3x) sec^2(3x)*(3)

=3[tan3x+sec^2(3x)/tan3x]