find derivativeof function of 1\√x
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Let f(x)=1√x , then y=1uandu=x12 , since √x=x12 . This means we have to differentiate both functions and multiply them. Let's start with y . By the power rule y'=1×u0=1 .
Answered by
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This function can be written as a composition of two functions, therefore we use the chain rule.
Explanation:
Let f(x)=√x , then y=1andu=x1/2 ,
since √x=x1/2 .
Simplifying further, we have that
y=uand=x−1/2
The chain rule states dy/dx=dy/du×du/dx
This means we have to differentiate both functions and multiply them. Let's start with
y .
By the power rule y'=1×u0=1 .
Now for u :Once again by the power rule we get:
Once again by the power rule we get:
u
'
=
−
1
2
×
x
−
1
2
−
1
u
'
=
−
1
2
x
−
3
2
u
'
=
−
1
2
√
x
3
f
'
(
x
)
=
y
'
×
u
'
f
'
(
x
)
=
1
×
−
1
2
√
x
3
f
'
(
x
)
=
−
1
2
√
x
3
Hopefully this helps
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