find derivatives of cos²x
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Let, y=cos2x .
Then, y can be written as y=(cosx)2 .
Now dydx=d(cosx)2dx
=>dydx=d(cosx)2d(cosx)∙d(cosx)dx [By chain rule]
=>dydx=2(cosx)1∙(−sinx)
=>dydx=−2(sinx)(cosx)=−sin2x
Therefore the differentiation of cos2x is −sin2x
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