Question

find derivatives of (sin)²wrtx and (5x²+3x-1)(x-1)wrt.x

Answer 1

Derivative of sin^2x = 2sinxcosx = sin2x
And Derivative of 2nd function u firstly open the bracket after u differentiate wrt x

Answer 2

as like a^2=a.a

sin^2x is the product of sinx.sinx

and as diff. of P.Q is given as P'Q+PQ'

and diff. of sinx=cosx

we get
diff.sin^2x= sinx.cosx+cosx.sinx =2sinxcosx

and part 2

(5x^2+3x-1).(x-1)= 5x^3+3x^2-x - 5x^2 -3x +1= 5x^3-2x^2-4x+1

and as diff. of ax^n = nax^(n-1)

diff. it we get
15x^2-4x-4

if it helped mark it the best!! happy to help!