Question

Find derivatives xy-x³+y²=0

Answer 1

$xy - {x}^{3} + {y}^{2} = 0 \\ diff. \: \: \: w.r.t \: \: \: x \\ x \frac{dy}{dx} + y - 3 {x}^{2} + 2y \frac{dy}{dx} = 0 \\ \frac{dy}{dx} (x + 2y) = 3 {x}^{2} \\ \frac{dy}{dx} = \frac{3 {x}^{2} }{x + 2y}$