find Diagonal of a Square of Side 12cm.
Answers
Answered by
1
Pythagoras theorem
AB^2+BC^2=AC^2
144+144=AC^2
AC=16.97cm
AB^2+BC^2=AC^2
144+144=AC^2
AC=16.97cm
Answered by
0
(hypotenuse)^2 = (side)^2 + (side)^2
=(√12)^2+(√12)^2
=144+144
=288
(hypotenuse)^2=√288
d=16.97
Similar questions
Social Sciences,
8 months ago
Math,
8 months ago
English,
8 months ago
Math,
1 year ago
English,
1 year ago
Social Sciences,
1 year ago