Math, asked by salmangujjar036, 4 months ago

find diameter and volume of cylinder whose radius is equals to 5 cm and height equals to 10 cm​

Answers

Answered by Anonymous
9

AnswEr :

  • The diameter of a cylinder is 10 cm and the volume of a cylinder is 785.4 cm².

Explanation :

We are given with the radius of a cylinder as well as height of a cylinder, that is,

  • Radius of cylinder, r = 5 cm.

  • Height of cylinder, h = 10 cm.

We have to find out the diameter and Volume of a cylinder.

__________________________

First we will find the diameter of a cylinder.

We know that, if we are given with the radius of a cylinder we have the required formula, that is,

Diameter = 2r

Substituting the given values in the formula,

⇒ Diameter = 2 × 5

Diameter = 10

Now,

As we are given with the radius of a cylinder and height of a cylinder we know the required formula, that is,

Volume of cylinder = πr²h.

Substituting the given values in the formula,

⇒ Volume of cylinder = 22/7 × (5)² × 10

⇒ Volume of cylinder = 22/7 × 25 × 10

⇒ Volume of cylinder = 22 × 3.57 × 10

⇒ Volume of cylinder = 78.54 × 10

Volume of cylinder = 785.4

Hence, the diameter of a cylinder is 10 cm and the volume of a cylinder is 785.4 cm².

Answered by 360Degree
25

  \large\underline{ \underline{ \sf{ \maltese \: {Given:-}}}}

  • Radius of cylinder (r) = 5 cm
  • Height of cylinder (h) = 10 cm

 \large\underline{ \underline{ \sf{ \maltese \: {To \: find\:-}}}}

  • Diameter and volume of the cylinder

 \large\underline{ \underline{ \sf{ \maltese \: {Solution:-}}}}

~ Diameter of a cylinder

We know that:-

\qquad \bull  \: \bf{Diameter = 2r}

\\

 \qquad \quad {: } \longrightarrow \sf{Diameter =   \bigg(2 \times 5 \bigg) \: {cm} } \\

 \\

 \qquad \quad {: } \longrightarrow  \underline{ \boxed{\sf{Diameter =   10\: {cm}} }} \\

~ Volume of cylinder

\qquad\bull  \: \bf{πr²h}

 \\

 \qquad \quad {: } \longrightarrow \sf{ Volume  \: of  \: cylinder =  \dfrac{22}{7} ×  {5}^{2}  × 10} \\

 \\

 \qquad \quad {: } \longrightarrow \sf{ Volume  \: of  \: cylinder =  \dfrac{22}{7}  × 25 × 10} \\

 \\

 \qquad \quad {: } \longrightarrow \sf{ Volume  \: of  \: cylinder = 22 × 3.57 × 10} \\

 \\

 \qquad \quad {: } \longrightarrow \sf{ Volume  \: of  \: cylinder = 78.54 × 10}\\

 \\

 \qquad \quad {: } \longrightarrow  \underline{ \boxed{\sf{ Volume  \: of  \: cylinder = 785.4 }} }\\

 \\

  \qquad\blacksquare  \: \sf{Diameter \: of \: the \: cylinder= \underline{\underline{10  \: cm}}}

  \qquad\blacksquare  \: \sf{Volume \: of \: the \: cylinder= \underline{\underline{785.4  \: cm}}}

\large\underline{ \underline{ \sf{ \maltese \: {Answer:-}}}}

  • Diameter of the cylinder is 10 cm
  • Volume of the cylinder is 785.4 cm
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