Find differentiation of √(ax+b)^m.
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What is the derivative of (ax+b) ^3?
Well, the question isn't completely stated. I'll assume you want the derivative with respect to x
y = (ax+b)^3
Let u = ax+b
We can now rewrite the function as;
y = u^3
:. dy/dx = dy/du × du/dx
dy/du = 3u^2
du/dx = a
=> dy/dx = 3u^2 (a)
=3au^2
But u = ax+b
:. dy/dx = 3a (ax+b)^2.
QED.
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