Question

find differentiation of cosecx secx cotx

Answer 1

cosec sec cot = (1/sin)(1/cos)(cos/sin)=1/sin²=cosec²

So, differentiation is 2cosec (-cosec cot)=-2cosec² cot

Answer 2

1). Cosec x define the relation between Hypotenuse and perpendicular of triangle.ie= H/P

2). sec x define the realation betwwen hypotenuse and Base of triangle. ie= H/B

3), cot x it define the relation between base and perpendicular of triangle. Ie= B/P