Question

find differentiation of x= at^2+bt+t with respect to t



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Answer 1

Answer:

wait for few minutes

Step-by-step explanation:

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Answer 2

Answer:

Given, position of the body x = at + bt^2

Instantaneous Velocity of a body is the rate of change of the position of the body.

So, v = dx/dt (differentiation of x w.r.t. t)

or, v = a + 2bt

Now, Instantaneous acceleration of the body is the rate of change of the velocity of the body.

So, a = dv/dt (differentiation of v w.r.t. t)

or, a = 2b

So, the instantaneous acceleration of the body is 2b.