Question

find dimension of electric field intensity

Answer 1

Answer:

Explanation:

“Every charge in the universe exerts a force on every other charge in the universe” is a bold yet true statement of physics. One way to understand the ability of a charge to influence other charges anywhere in space is by imagining the influence of the charge as a field. Note that this ‘influence’ is simply the electrostatic force that a charge is able to exert over another. However when describing fields, we require a quantity (scalar or vector), that is independent of the charge it is acting on and only dependent on the influence and the spatial distribution.

So in a simple way we can define the electrostatic field considering the force exerted by a point charge on a unit charge. In other words we can define the electric field as the force per unit charge.

To detect an electric field of a charge q, we can introduce a test charge q0 and measure the force acting on it.

F→ = 14 π ε0qq0r2r^

Thus the force exerted per unit charge is:

E→ = F→q0 = 14 π ε0qr2r^

Note that the electric field is a vector quantity that is defined at every pint in space, the value of which is dependent only upon the radial distance from q.

The test charge q0 itself has the ability to exert an electric field around it. Hence, to prevent the influence of the test charge, we must ideally make it as small as possible.

Thus,

E→

=limq0→0F→q0 = limq0→014 π ε0qq0r2r^×1q0 = 14 π ε0qr2r^

This is the electric field of a point charge. Also, observe that it exhibits spherical symmetry since the electric field has the same magnitude on every point of an imaginary sphere centered around the charge q.

Electric Field

Electric field due to positive and negative charges