Question

Find dimensions of x and y.​

Answer 1

[Mgh /nxT] = [M^0 L^0 T^0 mol^0]

=> [x] = [M][g][h] / {[n] [T]}

= [M][L T^(-2)][L] [mol^(-1)][K^(-1)]

= [M^(1) L^(2) T^(-2) K^(-1) mol^(-1)]...... ans...



again, putting the dimensions of terms in
P = n x^y T / V....

we get ... y = 1...

Answer 2

x will have the dimension of energy per mole per kelvin
ML2T-2 mol-1 kelvin-1